Question

In a dairy, there are $60$ cows and buffalos. The number of cows is twice that of buffalos. Buffalo $X$ ranked seventeenth in terms of milk delivered. If there are $9$ cows ahead of Buffalo $X$, how many buffalo's are after in rank in terms of milk delivered?

• A. $10$
• B. $11$
• C. $12$
• D. $13$

Answer 1

The correct option is C $12$

Let no. of cows $=$ $C$ and no.of buffaloes $=B$
Given : $C+B=60$ & $C=2B\Rightarrow B=20$ & $C=40$
Buffalo $X$ is ${17}^{th}$ in rank => $16$ cows and buffaloes are ahead of $X$ in milk delivered.
In these $16,9$ are cows(given) $\Rightarrow 7$ buffaloes are ahead of $X$ in milk delivered.
Since total no. of buffaloes($B$) is $20$ and $7$ buffaloes are above $X$, the no. of buffalo's that are below or after in rank of $X=20-8=12$.
Hence, option 'C' is correct.