Question

In a $\Delta ABC,\angle B={90}^{\circ }.$ Then, which of the following is true?

• A. sin A = cos C
• B. sin A = cosec C
• C. cos A = cot C
• D. cos A = sec C

Answer 1

The correct option is A sin A = cos C

$\begin{array}{ccccccc}& sin& cos& tan& cosec& sec& cot\\ \angle A& \frac{BC}{AC}& \frac{AB}{AC}& \frac{BC}{AB}& \frac{AC}{BC}& \frac{AC}{AB}& \frac{AB}{BC}\\ \angle C& \frac{AB}{AC}& \frac{BC}{AC}& \frac{AB}{BC}& \frac{AC}{AB}& \frac{AC}{BC}& \frac{BC}{AB}\end{array}$
From the table and the options given,
sin A = cos C is the correct option.