If Two Sides of a Triangle Are Unequal, Then the Angle Opposite to the Greater Side Is Greater Than Angle Opposite to the Smaller Side
In a Δ ABC,...
Question
In a ΔABC, BD is the median to the side AC, BD is produced to E such that BD = DE.
Hence, AE parallel to BC.
State whether the above statement is true or false.
A
True
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B
False
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Solution
The correct option is A True Given: △ABC, BD is median on AC. BD produced to E BD=DE. To prove: AE∥BC In △AED and △BDC, ∠ADE=∠BDC (Vertically opposite angles) AD=DC (D is mid point of AC) BD=DE (Given) Hence, △AED≅△BEC (SAS rule) Thus, ∠DAE=∠DCB (By cpct) but these are alternate angles w.r.t. AE and BC. Hence, AE∥BC