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Question
In a dihybrid cross, pure red-long pollen pea plant was crossed with white-short pollen pea plant. If linkage between the two genes were 66%, then calculate the number of white-long pollen plant among a total progeny of 1000.
In a dihybrid cross, pure red-long pollen pea plant was crossed with white-short pollen pea plant. If linkage between the two genes were 66%, then calculate the number of white-long pollen plant among a total progeny of 1000.
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Solution
The correct option is B 170
Given,The linkage between the two genes= 66%Therefore, the parental type i.e. pure red-long pollen pea plants and white-short pollen pea plants will be = 66% of 1000 =660 pea plantsAmong 660 parental type, 330 plants will be red-long pollen pea plant and 330 will be white-short pollen pea.Now, number of recombinant type pea plants i.e white-long pollen pea plants and red short pollen pea plants = 1000-660 = 340Taking equal number of white-long pollen pea plants and red short pollen pea plants, the number of white pollen plant = 340/2 = 170.Thus, the correct answer is '170.'
Given,
The linkage between the two genes= 66%
Therefore, the parental type i.e. pure red-long pollen pea plants and white-short pollen pea plants will be = 66% of 1000
=660 pea plants
Among 660 parental type, 330 plants will be red-long pollen pea plant and 330 will be white-short pollen pea.
Now, number of recombinant type pea plants i.e white-long pollen pea plants and red short pollen pea plants = 1000-660
= 340
Taking equal number of white-long pollen pea plants and red short pollen pea plants, the number of white pollen plant = 340/2
= 170.
Thus, the correct answer is '170.'
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