In a face centered cubic lattice, atom A occupies the corner positions and atom B occupies the face centered positions. If one atom of B is missing from one of the face centered points, the formula of the compound is

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Solution

As the molecule is having FCC structure,therefore let the formula of the compound be AxBy no of atom of A=1/88=1 number of atom of B=61/2 -1/2=5/2,As one atom is missing and ,where the contribution of each atom in FCC is ½. Thus the formula is A1B5/2 or A2B5

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In a face centered cubic lattice, atom A occupies the corner positions and atom B occupies the face centered positions. If one atom of B is missing from one of the face centered points, the formula of the compound is

As the molecule is having FCC structure,therefore let the formula of the compound be AxBy no of atom of A=1/8*8=1 number of atom of B=6*1/2 -1/2=5/2,As one atom is missing and ,where the contribution of each atom in FCC is ½. Thus the formula is A1B5/2 or A2B5

As the molecule is having FCC structure,therefore let the formula of the compound be AxBy no of atom of A=1/88=1 number of atom of B=61/2 -1/2=5/2,As one atom is missing and ,where the contribution of each atom in FCC is ½. Thus the formula is A1B5/2 or A2B5