Question

In a first order reaction, $10$% of the reactant is consumed in $25$ minutes. Calculate:
The time required for completing $17$% of the reaction.

Answer 1

Again, for the given reaction
$K=\frac{2.303}{t}\log \frac{a}{a-x}$

$t=\frac{2.303}{0.0042145}\log \frac{100}{100-17}$

$t=44.21minutes$.

$\therefore$ time required for completing $17$% of the reaction is $44.21$ minutes.