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Structure of an Atom

In a fission ...

Question

In a fission process, nucleus A divides into two nuclei B and C, their binding energies being $E_{a^{*}}$ $E_{b}$ and $E_{c}$ respectively. Ihen

E_{b} + E_{c} = E_{a}

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E_{b} + E_{c} > E_{a}

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E_{b} + E_{e} < E_{a}

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E_{b} E_{c} = E_{a}

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Solution

The correct option is A $E_{b} + E_{c} = E_{a}$
$\begin{matrix} E_{b} + E_{c} > E_{a} ∵ s o m e e n e r g y i s g o e n i n b r e a k i n g n u c l i e o f A H e n c e, o p t i o n A i s c o r r e c t a n s w e r . \end{matrix}$

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A

B

C

E_{a}, E_{b}

E_{c}

A

B

C

E_{a}

E_{b}

E_{c}

If $E_{A}, E_{B}, E_{C} a n d E_{D}$ represent the magnitudes of electric fields at A, B, C and D. Which of the options are correct?

\to E

E_{A}, E_{B}

E_{C}

2 A^{⊝} + B_{2} \to 2 B^{⊝} + A_{2}; 2 C^{⊝} + B_{2} \to N o r e a c t i o n; 2 D^{⊝} + A_{2} \to 2 A^{⊝} + D_{2}

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