In a fission reaction
$_{92}^{238} U \to^{117} X +^{117} Y + n + n$
the binding energy per nucleon of X and Y is 8.5 MeV whereas that of $^{236} U$ is 7.6 MeV. The total energy liberated will be about

200 keV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 Mev

No worries! We‘ve got your back. Try BYJU‘S free classes today!

200 MeV

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2000 MeV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
200 MeV

Binding energy of X = 8.5 $\times$ 117 = 994.5 MeV and of Y = 8.5 $\times$ 117 = 994.5 MeV. Total binding energy of X + Y = 1989 MeV. Now, binding energy of U - 236 = 7.6 $\times$ 236 = 1793.6 MeV. Energy liberay=ted = 1989 - 1793.6 = 195.4 MeV.
Hence the closest choice is (c)

Suggest Corrections

Similar questions

Q. In a fission reaction

_{92}^{236} U \to^{117} X +^{117} Y + n + n

, the binding energy per nucleon of X and Y is 8.5 MeV whereas of 236 U is 7.6 MeV. The total energy liberated will be about

In a fission reaction
$_{92}^{238} U \to^{117} X +^{117} Y + n + n$
the binding energy per nucleon of X and Y is 8.5 MeV whereas that of $^{236} U$ is 7.6 MeV. The total energy liberated will be about

Q. In a fission reaction

_{92}^{236} U \to

^{117} X +

^{117} Y + n + n

the average binding energy per nucleon of

X

and

Y

8.5 M e V

whereas that of

^{236} U

7.6 M e V

.
The total energy liberated will be about :

In a fission reaction $_{92} U^{236} \to X^{117} + Y^{117} + 2_{0} n^{1} + ε,$ The binding energy per nucleon of X and Y is 8.5 MeV where as of $_{92} U^{236}$ is 7.6 MeV. The total energy liberated will be about

Q. The binding energy per each nucleon in the neighborhood of medium nuclei is

8.5 M e V

and the binding energy per each nucleon is about

7.6 M e V

in the neighborhood of Uranium. The energy released in the fission of

U^{236}

is roughly

Join BYJU'S Learning Program

In a fission reaction 23892U→ 117X+117Y+n+n the binding energy per nucleon of X and Y is 8.5 MeV whereas that of 236U is 7.6 MeV. The total energy liberated will be about

The correct option is C 200 MeV Binding energy of X = 8.5 × 117 = 994.5 MeV and of Y = 8.5 × 117 = 994.5 MeV. Total binding energy of X + Y = 1989 MeV. Now, binding energy of U - 236 = 7.6 × 236 = 1793.6 MeV. Energy liberay=ted = 1989 - 1793.6 = 195.4 MeV. Hence the closest choice is (c)

In a fission reaction
$_{92}^{238} U \to^{117} X +^{117} Y + n + n$
the binding energy per nucleon of X and Y is 8.5 MeV whereas that of $^{236} U$ is 7.6 MeV. The total energy liberated will be about