Question

# in a flight of 2800 km , aircraft was slowed down due to bad weather. its average speed is reduced by 100km/h and time increased by 30 mins. find original duration of flight.

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Solution

## speed of aircraft= x Distance = 2800 km Time = Distance / Speed = 2800/x Given: The speed has reduced by 100 and time is increased by 30 min time taken at normal speed = 2800/x hr 30 min = 30/60 hr = 1/2 hr time taken after the speed was slowed down 2800/x - 100 hr now, as per question, time taken after the speed was slowed down =normal time taken +30min 2800/x-100 = 2800/x + 1/2hour or 2800/x-100 - 2800/x = 1/2 or (2800x - 2800x + 280000) / x2-100x = 1/2 or 280000 / x2-100x = 1/2 or 560000 = x2-100x or x2-100x-560000 = 0 or x2-800x+700x-560000 = 0 or x(x-800) + 700(x-800) = 0 or (x+700) (x-800) = 0 so x = 800 so original duration of the flight = 2800/800 hr = 3 hr 30 min

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