In a frequency distribution, the mid value of a class is 10 and the width of the class is 6. Then find the lower limit of the class.

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Solution

Lower limit of the class is $= 10 - (\frac{6}{2})$
$= 10 - 3 = 7$ $[1 m a r k]$

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In a frequency distribution, the mid value of a class is 10 and the width of the class is 6. Then find the lower limit of the class.

Lower limit of the class is =10−(62) =10−3=7 [1 mark]

Lower limit of the class is $= 10 - (\frac{6}{2})$
$= 10 - 3 = 7$ $[1 m a r k]$