Question

In a frequency distribution, the mid-value of a class is 10 and width of each class is 6. The lower limit of the class is
(a) 6
(b) 7
(c) 8
(d) 12

Answer 1

(b) 7

Given:
Mid value of the class = 10
Width of each class = 6
Now,
Let the lower limit be x.
We know:
Upper limit = Lower limit + Class size
= x + 6
Also,
$$\begin{gathered} \mathrm{Mid}\mathrm{value}=\frac{x+x+6}{2}=\frac{2x+6}{2}=x+3 \\ \Rightarrow x+3=10 \\ \Rightarrow x=7 \end{gathered}$$

Thus, the lower limit is 7.