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Question

In a frequency distribution, then mid value of a class intervals is 5 and the width of the class interval is 6 the lower limt of the class-interval is

A
2
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B
3
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C
4
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D
6
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Solution

The correct option is A 2
Let the lower limit of the class interval is l and the upper limit is u

Mid-value of the class interval is 5

l+u2=5

l+u=10 ................. (1)

Width of the interval is 6

ul=6 ................... (2)

Subtract equation (2) from (1),

2l=4

l=2


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