In a galvanometer 5% of the total current in the circuit passes through it. If the resistance of the galvanometer is G, the shunt resistance 5 connected to the galvanometer is:
A
19G
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B
G19
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C
20G
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D
G20
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Solution
The correct option is AG19 Shunt of an ammeter, S=Ig×GI−Ig =5×G100−5 =G19