In a game of carom, there are 10 white dice, 10 black dice and 1 red. What is the probability that the striker will hit red dice, if all the dices are uniformly distributed over the board?

\frac{1}{21}

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\frac{10}{21}

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\frac{20}{21}

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None of these

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Solution

The correct option is A $\frac{1}{21}$
$n (s) = 10 + 10 + 1 = 21$
$n (E) = 1$
$P (E) = \frac{1}{21}$

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In a game of carom, there are 10 white dice, 10 black dice and 1 red. What is the probability that the striker will hit red dice, if all the dices are uniformly distributed over the board?

The correct option is A 121n(s)=10+10+1=21n(E)=1P(E)=121

The correct option is A $\frac{1}{21}$
$n (s) = 10 + 10 + 1 = 21$
$n (E) = 1$
$P (E) = \frac{1}{21}$