Question

In a game of chance, a spinning arrow comes to rest at one of the number $1,2,3,4,5,6,7,8$
All these are equally likely outcomes. Find the probability that it will rest at
(1) $8$
(2) an odd number
(3) a number greater than $2$

Answer 1

$\left(1\right)$ $\frac{1}{8}\left(\frac{Favorablechoices}{Totalchoices}\right)$

$\left(2\right)$ $\frac{4}{8}=\frac{1}{2}(odd=1,3,5,7)$

$\left(3\right)$ $\frac{6}{8}=\frac{3}{4}$.