In a house, 3 bulbs of 25 W each are used for 5 hours a day. Calculate the unit of electricity consumed in a month of 32 days. Also, find the total expenditure if 1 unit of electricity costs ₹ 2.50.

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Solution

Step 1: Data provided,
$N u m b e r o f b u l b s = 3 P o w e r o f e a c h b u l b = 25 w a t t U \sin g t i m e i n d a y = 5 h o u r s T o t a l n u m b e r o f d a y s i n t h e g i v e n m o n t h = 31 C o s t o f 1 u n i t o f e l e c t r i c i t y = ₹ 2.50 .$
Step 2: Formula used,
$E l e c t r i c a l e n e r g y = E l e c t r i c a l p o w e r \times t i m e, a n d 1 u n i t o f e l e c t r i c i t y = 1000 w a t t h o u r$
Step 3: Calculation,
$E l a c t r i c a l e n e r g y c o n s u m e d b y 1 b u l b i n a m o n t h = (25 W a t t) \times (31 \times 5 h o u r s) = 3875 W a t t h o u r s = 3.875 k W h = 3.875 u n i t E l a c t r i c a l e n e r g y c o n s u m e d b y 3 b u l b i n a m o n t h = 3 \times 3.875 u n i t = 11.625 u n i t T o t a l \cos t = ₹ 2.50 \times 11.625 = ₹ 29.0625$
Hence, the electrical energy consumed by all the three bulbs is ₹ $29.06$

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