In a house there are six $100 W$ bulb, which are used for $6 h o u r s$ per day. Calculate the energy consumed in $k W h$ in a day.

3.6 k W h

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3600 k W h

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36 k W h

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360 k W h

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Solution

The correct option is A $3.6 k W h$
Power consumed by 1 bulb = $100 W$
Power consumed by 6 bulbs = $100 \times 6$
$= 600 W$
Time for which the bulbs are used = $6 h o u r s / d a y$
$E n e r g y c o n s u m e d p e r d a y$
$= \frac{P o w e r (W) \times t i m e (h o u r s)}{1000}$
$= \frac{600 \times 6}{1000}$
= $3.6 k W h$

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