In a hydraulic lift- the force exerted on the piston with small cross-sectional area F 1 is less than the force exerted on the piston with large cross-sectional area F 2- Then-A- Work done by F 1 is greater than work done by F 2B- Work done by F 2 is greater than work done by F 1C- No work is done by F1 or F2D- Work done by F1 is equal to work done by F2

You visited us 2 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Physics

Pascal's Law

In a hydrauli...

Question

In a hydraulic lift, the force exerted on the piston with small cross-sectional area $(F_{1})$ is less than the force exerted on the piston with large cross-sectional area $(F_{2})$ . Then,

Work done by $F_{1}$ is greater than work done by $F_{2}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Work done by $F_{2}$ is greater than work done by $F_{1}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

No work is done by $F_{1}$ or $F_{2}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Work done by $F_{1}$ is equal to work done by $F_{2}$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
Work done by $F_{1}$ is equal to work done by $F_{2}$

The energy can neither be created nor destroyed. Therefore, work done by the force, $F_{1}$ is equal to the work done by the force, $F_{2}$ .

Suggest Corrections

Similar questions

Q. Question 15
An apple falls from a tree because of gravitational attraction between the earth and apple. If

F_{1}

is the magnitude of force exerted by the earth on the apple and

F_{2}

is the magnitude of force exerted by apple on earth, then

(a)

F_{1}

is very much greater than

F_{2}

(b)

F_{2}

is very much greater than

F_{1}

(c)

F_{1}

is only a little greater than

F_{2}

(d)

F_{1}

and

F_{2}

are equal

An apple of mass 100 g falls from a tree because of gravitational attraction between the earth and the apple. If the magnitude of force exerted by the earth on the apple be $F_{1}$ and the magnitude of force exerted by the apple on the earth be $F_{2}$ , then :
(a) $F_{1}$ is very much greater than $F_{2}$
(b) $F_{2}$ is very much greater than $F_{1}$
(c) $F_{1}$ is only a little greater than $F_{2}$
(d) $F_{1}$ and $F_{2}$ are exactly equal

Q. Three forces are acting on the block as shown in figure.

Find work done by net force if block moves

10 m

in horizontal direction. Given that

[F_{1} = 20 N, F_{2} = 5 \sqrt{2} N, F_{3} = 10 N]

Q. An apple falls from a tree because of gravitational attraction between the earth and apple. If F1 is the magnitude of force exerted by the earth on the apple and F2 is the magnitude of force exerted by apple on earth, then.

Q. Three forces act on block as shown in figure.

Find work done by net force, if the block moves

10 m

in horizontal direction
Given magnitudes of forces are
[

F_{1} = 20 N, F_{2} = 5 \sqrt{2} N, F_{3} = 10 N

]

Join BYJU'S Learning Program

In a hydraulic lift, the force exerted on the piston with small cross-sectional area(F1) is less than the force exerted on the piston with large cross-sectional area(F2). Then,

The correct option is D Work done by F1 is equal to work done by F2 The energy can neither be created nor destroyed. Therefore, work done by the force, F1 is equal to the work done by the force, F2.

In a hydraulic lift, the force exerted on the piston with small cross-sectional area $(F_{1})$ is less than the force exerted on the piston with large cross-sectional area $(F_{2})$ . Then,

The correct option is D
Work done by $F_{1}$ is equal to work done by $F_{2}$

The energy can neither be created nor destroyed. Therefore, work done by the force, $F_{1}$ is equal to the work done by the force, $F_{2}$ .