In a laboratory, the count of bacteria in a certain experiment was increasing at the rate of 2.5% per hour. Find the number of bacteria at the end of 2 hours if the initial count was 5,06,000.
Using concept of compound interest, we shall find the number of bacteria at the end of 2 hours(A).
A = P × [1+R100]n
where, P is the initial count of bacteria, R is the rate at which bacteria count increases, n is the number of hours
P = 5,06,000
R = 2.5%
n = 2
A = 506000 × [1+2.5100]2
A = 5,31,616 approx.