wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In a Lloyd's single mirror experiment, the distance between the slit source and its image is 5 mm. The screen is at a distance of 1 m from the source. The fringe width is observed to be 0.1 mm. Then the wavelength of light used is


A
5460 A
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
5000 A
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
6460 A
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
4000 A
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 5000 A

In Lloyd's single mirror experiment, the image formed by the mirror I acts as the second source at a phase difference of π with S (due to reflection). Therefore, interference is observed only in the limited region.
Fringe width is given by the same formula.
β=λDd
λ=βdD=0.1×103×15×103
=5×107 m=5000 A

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Fringe Width
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon