In a metal chloride, the weight of metal and chlorine are in the ratio of $1 : 2$ . The equivalent weight of the metal will be:

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35.5

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106.5

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17.75

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Solution

The correct option is D 17.75
The relationship between the weight and equivalent weight for the metal and chlorine is:

$\frac{E q . w t o f m e t a l}{w t o f m e t a l} = \frac{E q . w t o f c h l o r i n e}{w t o f c h l o i n e}$ .

Given,
$\frac{w t o f m e t a l}{w t o f c h l o r i n e} = \frac{1}{2}$

Substituting values in this formula,

$\frac{E q . w t o f m e t a l}{1} = \frac{35.5}{2} E q . w t o f m e t a l = 17.75$

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