In a metallic triangular sheet ABC. AB = BC = L. If M is mass of sheet, what is the moment of inertia about AC

$\frac{m L^{2}}{4}$

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$\frac{m L^{2}}{12}$

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$\frac{m L^{2}}{6}$

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$\frac{m L^{2}}{18}$

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Solution

The correct option is B
$\frac{m L^{2}}{12}$

MoI of triangular sheet ABC about AC = $\frac{1}{2}$ moment of inertia of square ABCD about $A C = \frac{1}{2} (2 M) \frac{1^{2}}{12} = \frac{M I^{2}}{12}$

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In a metallic triangular sheet ABC. AB = BC = L. If M is mass of sheet, what is the moment of inertia about AC

The correct option is B mL212 MoI of triangular sheet ABC about AC = 12 moment of inertia of square ABCD about AC=12(2M)1212=MI212

The correct option is B
$\frac{m L^{2}}{12}$

MoI of triangular sheet ABC about AC = $\frac{1}{2}$ moment of inertia of square ABCD about $A C = \frac{1}{2} (2 M) \frac{1^{2}}{12} = \frac{M I^{2}}{12}$