In a meter bridge the null point is obtained at the middle point of the wire. If in one gap the resistance is 10Ω, then the value of resistance in the other gap is :-
A
10Ω
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B
5Ω
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C
15Ω
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D
500Ω
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Solution
The correct option is A10Ω If the null point is determined at B, then RS=l100−l according to question, l=50cm, so RS=50100−50=1 or R=S=10Ω (one resistance 10 Ω given)