In a mononuclear tetrahedral complex, optical isomerism cannot arise, unless:

all ligands are same

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all ligands are different

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the ligands are of two types

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the ligands are of three types

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Solution

The correct option is B all ligands are different
plane of polarized light will only rotate if there is no symmetry in the system. hence all ligands have to be different in a tetrahedral geometry to be optically active

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Similar questions

Q. Assertion :Tetrahedral complexes having two different types of unidentate ligands coordinated with central metal ion will show geometrical isomerism. Reason: Geometrical isomerism arises in homoleptic complexes due to different possible geometric arrangement of the ligands.

Q. Why is geometrical isomerism not possible in tetrahedral complexes having two different types of unidentate ligands coordinated with the central metal ion ?

Q. Assertion :Complexes containing three bidentate ligands do not show optical activity. Reason: Octahedral complex

[C o (N H_{3})_{4} C l_{2}] C l

shows geometrical isomerism.

Statement - 1: Complexes containing three bidentate ligands do not show optical activity.
Statement - 2: Octahedral complex $[C o (N H_{3})_{4} C l_{2}] C l$ shows geometrical isomerism.

Name the type of isomerism when ambidentate ligands are attached to central metal ion. Give two examples of ambidentate ligands.

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In a mononuclear tetrahedral complex, optical isomerism cannot arise, unless:

The correct option is B all ligands are differentplane of polarized light will only rotate if there is no symmetry in the system. hence all ligands have to be different in a tetrahedral geometry to be optically active

The correct option is B all ligands are different
plane of polarized light will only rotate if there is no symmetry in the system. hence all ligands have to be different in a tetrahedral geometry to be optically active