wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In a one-dimensional elastic collision, the relative velocity of approach before collision is equal to:

A
sum of the velocities of the bodies
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
e times the relative velocity of separation after collision
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1/e times the relative velocity of separation after collision
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
relative velocity of separation after collision
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D relative velocity of separation after collision

The Coefficient of Restitution is a measure of the "bounciness" of a collision between two objects: how much of the kinetic energy remains for the objects to rebound from one another vs. how much is lost as heat, or work done deforming the objects.

The coefficient, e is defined as the ratio of relative speeds after and before an impact, taken along the line of the impact:
e=velocity of separationvelocity of approach

The bodies stick together in perfectly inelastic collision and move together hence velocity of separation is zero.

(i) For perfectly elastic collision e = 1
(ii) For perfectly inelastic collision e = 0
(iii) For other collision 0 < e < 1

As elastic collision, therefore e=1 and hence relative velocity of separation=relative velocity of approach


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Realistic Collisions
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon