In a packet containing $400$ screws. $140$ screws are defective. A screw is picked up randomly from the packet. Then find the probability that the screw packed up is non-defective.

\frac{10}{20}

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\frac{13}{20}

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\frac{1}{20}

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\frac{3}{20}

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Solution

The correct option is A $\frac{13}{20}$
Total number of screws which are non defective are $400 - 140 = 260$
The probability of picking up a non defective screw is $\frac{260}{400} = \frac{13}{20}$

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In a packet containing 400 screws. 140 screws are defective. A screw is picked up randomly from the packet. Then find the probability that the screw packed up is non-defective.

The correct option is A 1320Total number of screws which are non defective are 400−140=260The probability of picking up a non defective screw is 260400=1320

In a packet containing $400$ screws. $140$ screws are defective. A screw is picked up randomly from the packet. Then find the probability that the screw packed up is non-defective.

The correct option is A $\frac{13}{20}$
Total number of screws which are non defective are $400 - 140 = 260$
The probability of picking up a non defective screw is $\frac{260}{400} = \frac{13}{20}$