In a parallelogram ABCD, angle A = 2x+25, angle B= 3x-5. Find the value of x, and he value of each angle in the parallelogram.

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Solution

Dear Student,

$A s ∠ A a n d ∠ B a r e a d j a c e n t a n g l e s i n t h e p a r a l l e \log r a m, t h e r e f o r e, ∠ A + ∠ B = 180 ° 2 x + 25 + 3 x - 5 = 180 5 x + 20 = 180 5 x = 180 - 20 5 x = 160 x = \frac{160}{5} = 32 ∠ A = ∠ C = (2 x + 25) ° = 89 ° \{A s o p p o s i t e a n g l e s i n p a r a l l e \log r a m a r e e q u a l\} ∠ B = ∠ D = (3 x - 5) ° = 91 ° \{A s o p p o s i t e a n g l e s i n p a r a l l e \log r a m a r e e q u a l\}$
Regards,

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