Question

In a parallelogram ABCD diagonals AC and BD intersects at O and AC =12.8 cm and BD=7.6 cm, then the measure of OC and OD respectively equal to

Answer 1

Since diagonals of a parallelogram bisect each other.

$\therefore OC=\frac{1}{2}\times AC=\frac{1}{2}\times 12.8=6.4cm$
$\text{Now,}OD=\frac{1}{2}\times BD=\frac{1}{2}\times 7.6=3.8cm$