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Question

In a parallelogram ABCD, If A =3x + 2° , B = 2x - 32° then find the value of x and then find the measures of C and D.

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Solution


Interior angles on the same side of the transversal are supplementary.
A +B = 180°
3x + 12° + 2x - 32° = 180°
5x-20=180°5x=200x=40°
Thus, A = 3×40°+12=132°
B=2x-32=2×40°-32=48°
Also, opposite angles of a parallelogram are congruent.
A=C=132°B=D=48°

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