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Question

In a parallelogram ABCD, M is the midpoint of side CD. A point N is chosen on DC extended such that, CN = MC and MN || AB What is the ratio of Area(ABCD):Area(ABNM)?


A
3 : 1
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B
1 : 2
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C
1 : 1
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D
2 : 1
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Solution

The correct option is C 1 : 1
Given,
MC is 12 of CD and CN = MC
MN=MC+CN=CD2+CD2=CD

As, it is given that MN || AB ,
ABMN is a parallelogram.

Now since the ABCD and ABMN are parallelograms between the same parallel lines and equal base, they have the same area.

Therefore, the ratio of their areas is 1:1.

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