1
Question
In a photo electric experiment 4 electrons with varying kinetic energy come out.
E1=1.6×10−19JE2=2.1×10−19JE3=3.2×10−19JE4=1.2×10−19J
The stopping potential , given this data will be
In a photo electric experiment 4 electrons with varying kinetic energy come out.
E1=1.6×10−19JE2=2.1×10−19JE3=3.2×10−19JE4=1.2×10−19J
The stopping potential , given this data will be
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Solution
Stopping potential is the potential required to stop the highest energy electrons from just hitting the collector.
The highest energy electron in the given setup is E3=3.2×10−19J
and energy is conserved , that we know for sure.
Initially the electron has kinetic energy = 3.2×10−19J
Finally it stops, so final K. E = 0
K.E. lost = 3.2×10−19J …(i)
P.E. gained = qΔV
= −1.6×10−19(0–V0)
= (1.6×10−19)V0 …(ii)
3.2×10−19=1.6×10−19V0
V0=2 volt.
Stopping potential is the potential required to stop the highest energy electrons from just hitting the collector.
The highest energy electron in the given setup is E3=3.2×10−19J
and energy is conserved , that we know for sure.
Initially the electron has kinetic energy = 3.2×10−19J
Finally it stops, so final K. E = 0
K.E. lost = 3.2×10−19J …(i)
P.E. gained = qΔV
= −1.6×10−19(0–V0)
= (1.6×10−19)V0 …(ii)
3.2×10−19=1.6×10−19V0
V0=2 volt.
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