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Standard XII

Physics

Stopping Potential

In a photoele...

Question

In a photoelectric cell, illuminated with a certain radiation, the minimum negative anode potential with respect to emitting metal required to stop the electron is 2 V. The maximum KE of the photoelectrons is:

0 eV

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1 eV

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2 eV

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4 eV

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Solution

The correct option is B 2 eV
Given,
$V_{0} = 2 V$
The minimum kinetic energy of the photo electron is $K_{m i n} = e V_{0}$
$K_{m i n} = 2 e V$
The correct option is C.

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In a photoelectric cell, illuminated with a certain radiation, the minimum negative anode potential with respect to emitting metal required to stop the electron is 2 V. The maximum KE of the photoelectrons is:

The correct option is B 2 eVGiven,V0=2VThe minimum kinetic energy of the photo electron is Kmin=eV0​Kmin=2eVThe correct option is C.

The correct option is B 2 eV
Given,
$V_{0} = 2 V$
The minimum kinetic energy of the photo electron is $K_{m i n} = e V_{0}$
$K_{m i n} = 2 e V$
The correct option is C.