In a plant species, flower colour yellow is dominant over white, and fruit shape round is dominant over elongated. Crossing was performed between two pure one having yellow-flower and round-fruit, and another with white flower and elongated-fruit. About $20$ plants survived in F $1$ progeny. Plants of F $1$ were allowed to self-fertilize, and about $960$ plants survived in F $2$ . If the traits follow Mendelian inheritance, the number of plants would have yellow-flower and round-fruit in F $1$ and F $2$ are respectively

20, 960

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20, 540

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10, 180

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10, 600

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Solution

The correct option is A $20, 540$
According to given information, the cross between two pure varieties yellow-flower and round-fruit (YYRR) and white flower and elongated-fruit (yyrr) would give all yellow-flower and round-fruit (YyRr) progeny in $F_{1}$ progeny. Selfing of YyRr would give "9 yellow-flower and round-fruit :3 yellow-flower and elongated-fruit :3 white flower and round-fruit :1 white flower and elongated-fruit" phenotypic ratio. Since 9 out of 16 progeny has yellow-flower and round-fruit in $F_{2}$ progeny; the total number of yellow-flower and round-fruit plants in $F_{2}$ progeny would be= 9/16 x 960= 540. Thus, the correct answer is option B.

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