Question

In a PNP transistor working as a common-base amplifier, current gain is 0.96 and emitter current is 7.2 $mA$. The base current is

• A. 0.4 $mA$
• B. 0.2 $mA$
• C. 0.29 $mA$
• D. 0.35 $mA$

Answer 1

The correct option is C 0.29 $mA$

$\alpha =\frac{i_c}{i_e}=0.96,i_e=7.2mA{i}_c=0.96\times i_e=0.96\times 7.2=6.91mA{i}_e=i_c+i_{b}7.2=6.91+i_b{i}_b=0.29mA$