Question

In a process 10 g of ice at $-5^{o}C$ is converted into the steam at ${100}^{o}C$. If specific heat of ice is $0.5cal{g}^{-1}{}^o{C}^{-1}$, then the amount of heat required to convert 10 g of ice from $-5^{o}C$ to $0^{o}C$ is :

• A. 15 cal
• B. 25 cal
• C. 50 cal
• D. 100 cal

Answer 1

Answer: (B)

25 cal

$C=0.5cal{g}^{-1}{}^o{C}^{-1}$

Heat required to rise the temperature of ice at $-5^{o}C$ to $0^{o}C$ is

$Q=mC\Delta T$

$=\left(10g\right)\left(0.5cal{g}^{-1}{}^o{C}^{-1}\right)$$\left(0^{o}C\right)-(-5^{o}C)$

$=25cal$