Question

In a process the pressure of a gas is inversely proportional to the square of the volume. If temperature of the gas increases, then work done by the gas:

• A. Is positive
• B. Is negative
• C. Is zero
• D. May be positive

Answer 1

The correct option is B Is negative

$P\propto \frac{1}{V^2}\Rightarrow P=\frac{k}{V^2}$
Now, $PV=nRT$
$\Rightarrow \frac{K}{V}=nRT$
$\therefore T\propto \frac{1}{V}$
$IfT\uparrow thenV\downarrow$
So, Work done negative.