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Standard XII
Physics
Projectile Time, Height and Range
In a projecti...
Question
In a projectile motion, the position vector is given by
→
r
=
6
t
^
i
+
(
8
t
−
5
t
2
)
^
j
; the range is
A
10
m
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B
10.5
m
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C
9.6
m
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D
96
m
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Solution
The correct option is
C
9.6
m
From the given equation we can write:
x
=
6
t
y
=
8
t
−
5
t
2
We know the range of the projectile is given by:
R
=
u
2
sin
2
θ
g
=
2.
u
sin
θ
.
u
cos
θ
g
R
=
2
u
x
u
y
g
As,
u
x
=
d
x
d
t
=
6
m
/
s
u
y
=
d
y
d
t
=
8
−
10
t
=
8
m
/
s
, as
t
=
0
⇒
R
=
2
×
6
×
8
10
=
9.6
m
Suggest Corrections
0
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