In a pure capacitive A.C circuit current and voltage differ in phase by

0^{o}

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45^{o}

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90^{o}

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180^{o}

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Solution

The correct option is C $90^{o}$
$i = i_{o} S i n (ω t + π / 2)$
current leads voltage by $π / 2$ i.e., current and voltage differ in phase by $90^{o}$

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Similar questions

List-I	List- II
(a) Phase difference between current and voltage in a purely resistive AC circuit	(i) π/2; current leads voltage
(b) Phase difference between current and voltage in a pure inductive AC circuit	(ii) zero
(c) Phase difference between current and voltage in a pure capacitive AC circuit	(iii) π/2; current lags voltage
(d) Phase difference between current and voltage in an LCR series circuit	(iv) ${tan}^{- 1} (\frac{X_{C} - X_{L}}{R})$

I = 4 s i n ω t

E = 150 c o s [ω t + \frac{π}{3}]

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