In a reaction, $C r_{2} O_{7}^{2 -}$ was reduced to $C r^{3 +}$ in acid medium. The concentration of $0.1$ M $C r_{2} O_{7}^{2 -}$ measured per litre (in N) is $x \times 10^{- 1}$ . Here, $x$ is :

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Solution

The balanced reaction is as follows:
$C r_{2} O_{7}^{- 2} \to C r^{+ 3}$
+6 +3
As we know,
Normality = Molarity x n-factor $= 6 \times 0.1 = 0.6$ N = $6 \times 10^{- 1}$ .
So, $x$ is $6$ .

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