Question

In a reaction vessel, 1.184 g of NaOH is required to be added for completing the reaction. How many millilitre of 0.15 M NaOH should be added for this requirement?

• A. 197.33 ml
• B. 297.33 ml
• C. 97.33 ml
• D. 107.33 ml

Answer 1

The correct option is A 197.33 ml

Amount of NaOH present in 1000 mL of 0.15 M NaOH = $0.15\times 40=6g$
$\therefore$ 1 mL of this solution contain $NaOH=\frac{6}{1000}$ g
$\therefore$ 1.184 g of NaOH will be present in $=\frac{1}{6\times {10}^{-3}}\times 1.184=197.33ml$
So, the correct answer will be option (a).