In a reaction with 31.9 g of copper sulphate solution completely reacts with 21.2 g of sodium carbonate solution. The products formed were some amount of copper carbonate and 28 g of sodium sulphate. If the reaction is carried an agreement with laws of conservation of mass, what will be the chemical equation of reaction and the mass of carbon carbonate formed ?

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Solution

Reaction of Copper sulphate react with sodium carbonate to form Copper carbonate and Sodium sulphate is as follows:

CuSO₄ + Na₂CO₃ → CuCO₃ + Na₂SO₄

Now, the reaction is in agreement with law of conservation of mass. It means

Mass of reactant = Mass of Product
Mass of Reactant = 31.9 (CuSO₄) + 21.2 g (Na₂CO₃)
= 53.1 g
Mass of Product = Mass of CuCO₃ + Mass of Na₂SO₄
53.1 = Mass of CuCO₃ + 28 g
Mass of CuCO₃ = 53.1 - 28
= 25.1 g

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