In a rectangle ABCD - AB -20 cm - - BAC -60 O- Then side BC -A- 20 cmB- 10 cm- 20 -3 cmD- 10 -3 cm

The correct option is C 20√(3) cm Let the breadth 'BC' be = x tan60^o = x/20 x=20√(3) ...

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In a rectangle ABCD, AB = 20 cm, $∠ B A C = 60^{O} .$ Then side BC =

$20 \sqrt{3}$ cm

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$10 \sqrt{3}$ cm

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20 cm

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10 cm

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