In a rectangle ABCD , $A B = x + y$ , $B C = x - y, C D = 9$ and $A D = 3$ , find value of x and y.

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Solution

AB=CD
$\Rightarrow x + y = 9$ .....(1)
AD=BC
$\Rightarrow x - y = 3$ .....(2)
Adding equations (1) and (2)
$2 x = 12$
$\Rightarrow x = 6$
Putting the value of x in equation (1)
$x + y = 9$
$y = 9 - x$
$y = 9 - 6$
$y = 3$
Values are, $x = 6, y = 3$

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In a rectangle ABCD ,AB=x+y,BC=x−y,CD=9 and AD=3, find value of x and y.

AB=CD⇒x+y=9.....(1)AD=BC⇒x−y=3.....(2)Adding equations (1) and (2)2x=12⇒x=6Putting the value of x in equation (1)x+y=9y=9−xy=9−6y=3Values are, x=6,y=3

In a rectangle ABCD , $A B = x + y$ , $B C = x - y, C D = 9$ and $A D = 3$ , find value of x and y.

AB=CD
$\Rightarrow x + y = 9$ .....(1)
AD=BC
$\Rightarrow x - y = 3$ .....(2)
Adding equations (1) and (2)
$2 x = 12$
$\Rightarrow x = 6$
Putting the value of x in equation (1)
$x + y = 9$
$y = 9 - x$
$y = 9 - 6$
$y = 3$
Values are, $x = 6, y = 3$