Question

In a rectangle $ABCD$ if $\angle A=(3x+3)$ and $\angle B=(4y+6),$ find the value of $x+y$

Answer 1

In given figure $ABCD$ is a rectangle.

Where, $\angle A=3x+3$ and $\angle B=4y+6$

$\Rightarrow$ $\angle A={90}^o$ [ All angles of rectangle is ${90}^o$ ]

$\Rightarrow$ $3x+3={90}^o$

$\Rightarrow$ $3x={87}^o$

$\therefore$ $x={29}^o$

$\Rightarrow$ $\angle B={90}^o$ [ All angles of rectangle is ${90}^o$ ]

$\Rightarrow$ $4y+6={90}^o$

$\Rightarrow$ $4y={84}^o$

$\therefore$ $y={21}^o$

$\Rightarrow$ $x+y={29}^o+{21}^o={50}^o$