Question

In a region of space, there is an electric field of ${10}^3{\text{NC}}^{-1}$ towards west. A body having deficient of ${10}^6$ electrons is lying in this region. The magnitude and direction of force acting on the body will be

• A. $1.6\times {10}^{-13}\text{N}\text{(towards west)}$
• B. $1.6\times {10}^{-13}\text{N}\text{(towards west)}$
• C. $1.6\times {10}^{-10}\text{N}\text{(towards east)}$
• D. $1.6\times {10}^{-10}\text{N}\text{(towards west)}$

Answer 1

The correct option is D $1.6\times {10}^{-10}\text{N}\text{(towards west)}$

Given, the object having deficient of ${10}^6$ electrons, means the object is a positively charged one.

Net charge of the object is, $q=ne$

$q={10}^6\times 1.6\times {10}^{-19}\text{C}$

Force experienced by the object is,

$F=qE={10}^3\times {10}^6\times 1.6\times {10}^{-19}$

$F=1.6\times {10}^{-10}\text{N}\text{(towards west)}$

As we know, positively charged body experience electrostatic force along the direction of electric field.

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, $\left(D\right)$ is the correct answer.