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Question

# In a region of space, there is an electric field of 103 NC−1 towards west. A body having deficient of 106 electrons is lying in this region. The magnitude and direction of force acting on the body will be

A
1.6×1013 N (towards west)
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B
1.6×1013 N (towards west)
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C
1.6×1010 N (towards east)
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D
1.6×1010 N (towards west)
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Solution

## The correct option is D 1.6×10−10 N (towards west)Given, the object having deficient of 106 electrons, means the object is a positively charged one. Net charge of the object is, q=ne q=106×1.6×10−19 C Force experienced by the object is, F=qE=103×106×1.6×10−19 F=1.6×10−10 N (towards west) As we know, positively charged body experience electrostatic force along the direction of electric field. <!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (D) is the correct answer.

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