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Question

In a regular hexagon ABCDEF, AB=a,BC=b and CD=c. Then, AE is equal to

A
a+b+c
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B
2a+b+c
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C
b+c
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D
a+2b+c
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Solution

The correct option is C b+c
We have
AB=a,BC=b and CD=c
AC=a+b
In ACD, we have
AC+CD=AD
a+b+c=AD
In AED, we have
AD+DE=AE
a+b+ca=AE [DE=BA=a]
AE=b+c
723924_680934_ans_4640093152684b299c071b5938100cbb.png

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