In a regular hexagon ABCDEF, AB=a,BC=b and CD=c. Then, AE is equal to
A
a+b+c
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B
2a+b+c
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C
b+c
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D
a+2b+c
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Solution
The correct option is Cb+c We have AB=a,BC=b and CD=c ∴AC=a+b In △ACD, we have AC+CD=AD ⇒a+b+c=AD In △AED, we have AD+DE=AE ⇒a+b+c−a=AE[∵DE=BA=−a] ⇒AE=b+c