Question

In a regular hexagon each corner is at a distance r from the centre. Identical charges of magnitude Q are placed at $5$ corners. The field at the centre is $(K=\frac{1}{4\pi {ϵ}^{}})$

• A. $KQ/r^2$
• B. $\frac{6KQ}{r^2}$
• C. $\frac{5KQ}{r^2}$
• D. Zero

Answer 1

The correct option is A $KQ/r^2$

Magnitude $=Q$

no. of corner $=5$

$K=\frac{1}{4\pi ϵ}$

distance $=r$

If charges were kept at all corners resultant electric field would have been $=0$

So, removal of one charge would result in the same electric field as due to one charge alone. So, $E=\frac{KQ}{r^2}$.