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Byju's Answer

Standard XII

Chemistry

Central Atom and Ligands

In a regular ...

Question

In a regular octahedral molecule, $M X_{6}$ the number of X-M-X bonds at $180^{0}$ is:

three

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Solution

The correct option is A three

There are 3 number of bonds of X-M-X at $180^{o}$ in regular octahedral molecule (as in the image above)

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Similar questions

In a regular octahedral molecule, $M X_{6}$ the number of X-M-X bonds at an angle of $180^{\circ}$ is

Q. The compound

M X_{6}

is octahedral. Find the number of

90^{o}

X - M - X angles in the compound.(If number is X then enter X/3)

Number of $σ s p^{2} - s p^{2}$ bonds pre3sent in a molecule of x in the process $C_{6} H_{6} H_{2} / N i - --- \to X$ is

O_{2}

molecule has

X

number of

σ

bond and

Y

number of

π

bond, then

X

and

Y

are respectively:

Q. Select the correct statement/s among the following?
(a) Order of bond length :

O_{2} < O_{2}^{+} < O_{2}^{- 2} < O_{2}^{+ 2}

(b) Number of

d π - p π

bonds in

S O_{2}

are 2
(c)

X e F_{2}, S O_{3}, X e F_{4}, S C l_{4},

have non-zero dipole moment
(d) Order of ionic nature

L i C l > N a C l > K C l > R b C L > C s C l

(e)

A B_{2} E_{2}

has square planar geometry
(f) Equal number of dative bonds in molecules are

N_{2} O, O_{3}, S O_{2}, B_{3} N_{3} H_{6}, [C u (N H_{3})_{4}] S O_{4}

(g) All electron deficient molecules of ‘B’ in

B_{2} H_{6}

undergo

s p_{2}

hybridization
(h) Central atom in a molecule has

6 b o n d e d p a i r s

and

0 l o n e p a i r s

then geometry is distorted octahedral geometry ___

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In a regular octahedral molecule, MX6 the number of X-M-X bonds at 1800 is:

The correct option is A threeThere are 3 number of bonds of X-M-X at 180o in regular octahedral molecule (as in the image above)

In a regular octahedral molecule, $M X_{6}$ the number of X-M-X bonds at $180^{0}$ is:

The correct option is A three

There are 3 number of bonds of X-M-X at $180^{o}$ in regular octahedral molecule (as in the image above)