Question

# In a resonance tube experiment, a closed organ pipe of length 120 cm resonates when tuned with a tuning fork of frequency 340 Hz. If water is poured in the pipe, then (velocity of sound in air is 340 m/s) Â

A
Minimum length of water column to have the resonance is 45 cm
B
The distance between two successive nodes is 50 cm
C
The maximum length of water column to create the resonance is 95 cm
D
The maximum length of water column to create the resonance is 45 cm

Solution

## The correct options are A Minimum length of water column to have the resonance is 45 cm B The distance between two successive nodes is 50 cm C The maximum length of water column to create the resonance is 95 cm From v=fλ ⇒340=340×λ⇒λ=1m For 1st resonance l1=λ4 ⇒I1 = 25 cm so, length of water column is 95 cm For 2nd resonance I2=3λ4=75 cm, so length of water column is (120 - 75) cm = 45 cm 3rd resonance won't be established as for that the length of air column required is I=5λ4=125 cm > length of tube Separation between consecutive nodes is λ2=50 cmPhysics

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