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Question

In a resonance tube experiment, a closed organ pipe of length 120 cm resonates when tuned with a tuning fork of frequency 340 Hz. If water is poured in the pipe, then (velocity of sound in air is 340 m/s)
 



A
Minimum length of water column to have the resonance is 45 cm
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B
The distance between two successive nodes is 50 cm
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C
The maximum length of water column to create the resonance is 95 cm
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D
The maximum length of water column to create the resonance is 45 cm
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Solution

The correct options are
A Minimum length of water column to have the resonance is 45 cm
B The distance between two successive nodes is 50 cm
C The maximum length of water column to create the resonance is 95 cm

From v=fλ
340=340×λλ=1m
For 1st resonance l1=λ4
I1 = 25 cm so, length of water column is 95 cm
For 2nd resonance I2=3λ4=75 cm, so length of water column is (120 - 75) cm = 45 cm
3rd resonance won't be established as for that the length of air column required is I=5λ4=125 cm > length of tube
Separation between consecutive nodes is λ2=50 cm

Physics

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